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Club filter : ウィキペディア英語版
Club filter
In mathematics, particularly in set theory, if \kappa is a regular uncountable cardinal then \operatorname(\kappa), the filter of all sets containing a club subset of \kappa, is a \kappa-complete filter closed under diagonal intersection called the club filter.
To see that this is a filter, note that \kappa\in\operatorname(\kappa) since it is thus both closed and unbounded (see club set). If x\in\operatorname(\kappa) then any subset of \kappa containing x is also in \operatorname(\kappa), since x, and therefore anything containing it, contains a club set.
It is a \kappa-complete filter because the intersection of fewer than \kappa club sets is a club set. To see this, suppose \langle C_i\rangle_ is a sequence of club sets where \alpha<\kappa. Obviously C=\bigcap C_i is closed, since any sequence which appears in C appears in every C_i, and therefore its limit is also in every C_i. To show that it is unbounded, take some \beta<\kappa. Let \langle \beta_\rangle be an increasing sequence with \beta_>\beta and \beta_\in C_i for every i<\alpha. Such a sequence can be constructed, since every C_i is unbounded. Since \alpha<\kappa and \kappa is regular, the limit of this sequence is less than \kappa. We call it \beta_2, and define a new sequence \langle\beta_\rangle similar to the previous sequence. We can repeat this process, getting a sequence of sequences \langle\beta_\rangle where each element of a sequence is greater than every member of the previous sequences. Then for each i<\alpha, \langle\beta_\rangle is an increasing sequence contained in C_i, and all these sequences have the same limit (the limit of \langle\beta_\rangle). This limit is then contained in every C_i, and therefore C, and is greater than \beta.
To see that \operatorname(\kappa) is closed under diagonal intersection, let \langle C_i\rangle, i<\kappa be a sequence of club sets, and let C=\Delta_ C_i. To show C is closed, suppose S\subseteq \alpha<\kappa and \bigcup S=\alpha. Then for each \gamma\in S, \gamma\in C_\beta for all \beta<\gamma. Since each C_\beta is closed, \alpha\in C_\beta for all \beta<\alpha, so \alpha\in C. To show C is unbounded, let \alpha<\kappa, and define a sequence \xi_i, i<\omega as follows: \xi_0=\alpha, and \xi_ is the minimal element of \bigcap_C_\gamma such that \xi_>\xi_i. Such an element exists since by the above, the intersection of \xi_i club sets is club. Then \xi=\bigcup_\xi_i>\alpha and \xi\in C, since it is in each C_i with i<\xi.
==References==

*Jech, Thomas, 2003. ''Set Theory: The Third Millennium Edition, Revised and Expanded''. Springer. ISBN 3-540-44085-2.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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